MIPS program is Not working Error: Symbol exit not found in the table

Question

.text
main:

check whether the second value that user entered is less than zero and if yes the exit the program

blez $t1, exit

Taking the first input from the user

la,$a0,InputValone
li,$v0,4
syscall

li,$v0,5
move $t0,$v0
syscall

Taking the second input from the user

la,$a0,InputValTwo
li $v0,4
syscall

li $v0,5
move $v0,$t1
syscall

multiply the two inputs

mul $t2,$t1,$t0
move $t3,$t0

loop:
    beq $t2,$t3, endloop    #if $t2==$t3, end the program
    add $t3,$t3,$t0     #else $t3=$t3+$t0

    b loop

    la      $a0,OutputValue
    li      $v0,4
    syscall

    move    $a0,$t3
    li      $v0,1
    syscall


    endloop:
.data
    InputValone: .asciiz "Enter Your First Value : "
    InputValTwo: .asciiz "Enter Your Second Value : "
    OutputValue: .asciiz "Output is : "

Answer 1

 endloop:
 .data

You do not really want to do this??

Using a jump instruction like blez $t1, exit or beq $t2,$t3, endloop you jump to a label.

Obviously the exit: label is missing.

And it is not defined which instruction follows the endloop: label:

Normal compilers (for real MIPS CPUs, not for MIPS emulators) would insert some dummy bytes between the last instruction of the code section and the .data section - just like that:

endloop:
  .word some_dummy_data
  .word some_dummy_data
  .word some_dummy_data
  .word some_dummy_data
  .word some_dummy_data
  ...
.data

The CPU would interpret that bytes as instructions and execute them...

You'll have to add the exit: label and youll have to add code after theendloop:` label:

exit:
endloop:
    li      $v0,<value that exits the program>
    syscall

Not knowing your simulator I cannot tell you the correct value for v0 for exiting the program. For Linux/MIPS a value of v0=4001 would be suitable...