from nsepy import get_history
from datetime import date
import datetime
import pandas as pd
import numpy as np
file = r'C:\Users\Raspberry-Pi\Desktop\Desktop\List.xlsx'
list = pd.read_excel(file)
list = list['SYMBOL']
start = date.today()-datetime.timedelta(days = 10)
end = date.today()
symb = get_history(symbol='INFY',start = start,end = end)
h = symb.tail(3).High.tolist()
l = symb.tail(3).Low.tolist()
print(type(h))
print(type(l))
x = map(lambda a,b:a-b,h,l)
print(type(x))
x = list(x)
I am getting error:
series object not callable
and its pointing to x = list(x) line.
list(x) normally means turn x into a list object. It's a function that creates a list object. But near the top you redefined list:
list = pd.read_excel(file)
Now list is now a pandas series object (as the error message says), and it does not function as a function, i.e. it is not callable, it cannot be used with ().
Use a different name for this object. Use a silly name like foo if you can't think of a better descriptor.
But I think you can omit map and use simple subtract and then convert to list:
symb = get_history(symbol='INFY',start = start,end = end)
print ((symb.tail(3).High - symb.tail(3).Low).tolist())
Also don't use variable list (reserved word in python) rather L (or something else):
L = pd.read_excel(file)
L = L['SYMBOL']
Sample:
import pandas as pd
symb = pd.DataFrame({'High':[8,9,7,5,3,4],'Low':[1,2,3,1,0,1]})
print (symb)
High Low
0 8 1
1 9 2
2 7 3
3 5 1
4 3 0
5 4 1
print ((symb.tail(3).High - symb.tail(3).Low).tolist())
[4, 3, 3]
EDIT:
I try simulate problem:
list = pd.DataFrame({'SYMBOL':['sss old','dd','old']})
print (list)
SYMBOL
0 sss old
1 dd
2 old
list = list['SYMBOL']
print (list)
0 sss old
1 dd
2 old
Name: SYMBOL, dtype: object
print (type(list))
<class 'pandas.core.series.Series'>
x = [1,2,3]
#list is Series, not function
x = list(x)
print (x)
TypeError: 'Series' object is not callable
If change list to L, is important reopen python console, because still same error.
So this works perfectly:
df = pd.DataFrame({'SYMBOL':['sss old','dd','old']})
print (df)
SYMBOL
0 sss old
1 dd
2 old
L = df['SYMBOL']
print (L)
0 sss old
1 dd
2 old
Name: SYMBOL, dtype: object
x = [1,2,3]
x = list(x)
print (x)
[1, 2, 3]
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