Without help from additional container (like vector), is it possible that I can make map's key sorted same sequence as insertion sequence?
#include <map>
#include <iostream>
using namespace std;
int main()
{
map<const char*, int> m;
m["c"] = 2;
m["b"] = 2;
m["a"] = 2;
m["d"] = 2;
for (map<const char*, int>::iterator begin = m.begin(); begin != m.end(); begin++) {
// How can I get the loop sequence same as my insert sequence.
// c, b, a, d
std::cout << begin->first << std::endl;
}
getchar();
}
No. A std::map is a sorted container; the insertion order is not maintained. There are a number of solutions using a second container to maintain insertion order in response to another, related question.
That said, you should use std::string as your key. Using a const char* as a map key is A Bad Idea: it makes it near impossible to access or search for an element by its key because only the pointers will be compared, not the strings themselves.
No. std::map<Key, Data, Compare, Alloc> is sorted according to the third template parameter Compare, which defaults to std::less<Key>. If you want insert sequence you can use std::list<std::pair<Key, Data> >.
As was pointed out, any sequential STL container would do: vector, deque, list, or in this particular case event string. You would have to decide on the merits of each.
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