I'm fairly new on Python.
I have 2 columns on a dataframe, columns are something like:
db = pd.read_excel(path_to_file/file.xlsx)
db = db.loc[:,['col1','col2']]
col1 col2
C 4
C 5
A 1
B 6
B 1
A 2
C 4
I need them to be like this:
1 2 3 4 5 6
A 1 1 0 0 0 0
B 1 0 0 0 0 1
C 0 0 0 2 1 0
so they act like rows and columns and values refer to the number of coincidences.
Say your columns are called cat
and val
:
In [26]: df = pd.DataFrame({'cat': ['C', 'C', 'A', 'B', 'B', 'A', 'C'], 'val': [4, 5, 1, 6, 1, 2, 4]})
In [27]: df
Out[27]:
cat val
0 C 4
1 C 5
2 A 1
3 B 6
4 B 1
5 A 2
6 C 4
Then you can groupby
the table hierarchicaly, then unstack it:
In [28]: df.val.groupby([df.cat, df.val]).sum().unstack().fillna(0).astype(int)
Out[28]:
val 1 2 4 5 6
cat
A 1 2 0 0 0
B 1 0 0 0 6
C 0 0 8 5 0
Edit
As IanS pointed out, 3 is missing here (thanks!). If there's a range of columns you must have, then you can use
r = df.val.groupby([df.cat, df.val]).sum().unstack().fillna(0).astype(int)
for c in set(range(1, 7)) - set(df.val.unique()):
r[c] = 0
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