Looping String difficulty python 3

Question

The function of this code is to capitalize letter that appears in the even indexed and lowercase the letter that appears in the odd indexed. Moreover, if whitespace appears between the words, the index has to be reset to 0. As you can see, the first and the second words are executed correctly. Whereas, the third word is incorrect. Instead of C and S being capitalized, 0 and 2 index respectively, A and E are capitalized.

string = 'Weird string case'
result = ''
i=0
for m in string:
    if(i%2==0):
       result = result+m.upper()
       i+=1
    elif(m==' '):
       result = result + m
       i=0
    else:
       result = result + m.lower()
       i+=1
    print(result)

Current Output

 WeIrD StRiNg cAsE

Expected Output

 WeIrD StRiNg CaSe

Answer 1

You should test if m is a space first; otherwise if the space occurs when i is even then i would not be reset:

string = 'Weird string case'
result = ''
i=0
for m in string:
    if(m==' '):
       result = result + m
       i=0
    elif(i%2==0):
       result = result+m.upper()
       i+=1
    else:
       result = result + m.lower()
       i+=1
    print(result)