laravel 5.7 how to pass request of controller to model and save

Question

I am trying to pass $request from a function in controller to a function in model.

THis is my controller function:

PostController.php

public function store(Request $request, post $post)
{

    $post->title = $request->title;
    $post->description = $request->description;

    $post->save();

    return redirect(route('post.index'));

}

how save data in model Post.php?

I want the controller to only be in the role of sending information. Information is sent to the model. All calculations and storage are performed in the model

Thanks

Answer 1

You can make it even easier. Laravel has it's own helper "request()", which can be called anywhere in your code.

So, generally, you can do this:

PostController.php

    public function store()
    {
        $post_model = new Post;
        // for queries it's better to use transactions to handle errors
        \DB::beginTransaction();
        try {
           $post_model->postStore();
           \DB::commit(); // if there was no errors, your query will be executed
        } catch (\Exception $e) {
            \DB::rollback(); // either it won't execute any statements and rollback your database to previous state
            abort(500);
        }
        // you don't need any if statements anymore. If you're here, it means all data has been saved successfully
        return redirect(route('post.index'));
    }

Post.php

    public function postStore()
    {
        $request = request(); //save helper result to variable, so it can be reused
        $this->title = $request->title;
        $this->description = $request->description;
        $this->save();
    }

---

I'll show you full best practice example for update and create:

web.php

    Route::post('store/post/{post?}', 'PostController@post')->name('post.store');

yourform.blade.php - can be used for update and create

    <form action='{{ route('post.store', ['post' => $post->id ?? null]))'>
       <!-- some inputs here -->
       <!-- some inputs here -->

    </form>

PostController.php

    public function update(Post $post) {
        // $post - if you sent null, in this variable will be 'new Post' result
        // either laravel will try to find id you provided in your view, like Post::findOrFail(1). Of course, if it can't, it'll abort(404)

        // then you can call your method postStore and it'll update or create for your new post.
        // anyway, I'd recommend you to do next

        \DB::beginTransaction();
        try {
          $post->fill(request()->all())->save();
          \DB::commit();
        } catch (\Exception $e) {
          \DB::rollback();
           abort(500);
        }
      return redirect(route('post.index'));
    }

Answer 2

Based on description, not sure what you want exactly but assuming you want a clean controller and model . Here is one way

Model - Post

class Post {
    $fillable = array(
        'title', 'description'
    );
}

PostController

class PostController extend Controller {

    // store function normally don't get Casted Objects as `Post`
    function store(\Request $request) {

        $parameters = $request->all(); // get all your request data as an array

        $post = \Post::create($parameters); // create method expect an array of fields mentioned in $fillable and returns a save dinstance
        // OR
        $post = new \Post();
        $post->fill($parameters);
    }
}

I hope it helps