Consider m = [1 2 3; 4 5 6; 7 8 9]
for idx in eachindex(m)
println(idx)
end
I was expecting it to print (1, 1) (2, 1), (3, 1) .... (1, 3), (2, 3), (3, 3) but it prints 1, 2, ..., 9.
What's the most elegant way to loop through all the indices of a multidimensional array?
What about
julia> for i in CartesianIndices(m)
println(Tuple(i))
end
(1, 1)
(2, 1)
(3, 1)
(1, 2)
(2, 2)
(3, 2)
(1, 3)
(2, 3)
(3, 3)
(You can access the tuple of subindices of i::CartseianIndex with Tuple(i).)
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With