JS turning a function into an object without using "return" in the function expression

Question

i have seen in a framework (came across it once, and never again) where the developer defines a module like this:

core.module.define('module_name',function(){
    //module tasks up here
    this.init = function(){
        //stuff done when module is initialized
    }
});

since i never saw the framework again, i tried to build my own version of it and copying most of it's aspects - especially how the code looked like. i tried to do it, but i can't seem to call the module's init() because the callback is still a function and not an object. that's why i added return this

//my version
mycore.module.define('module_name',function(){
    //module tasks up here
    this.init = function(){
        //stuff done when module is initialized
    }

    //i don't remember seeing this:
    return this;
});

in mycore, i call the module this way (with the return this in the module definition):

var moduleDefinition = modules[moduleName].definition; //the callback
var module = moduleDefinition();
module.init();

how do i turn the callback function into an object but preserve the way it is defined (without the return this in the definition of the callback)?

Answer 1

you have to use:

var module = new moduleDefinition();

and then you're going to get an object.

Oh, and maybe you want to declare init as this:

this.init = function() {

Cheers.