I got a weird problem, probably I am missing something here.
I got a list of elements, one part of it is visible, the other is invisible.
I want to select the last 3 elements of the invisible part. I added a snipped to illustrate the issue.
The result I am looking for is for 10, 11, 12 to be shown after the js ran, not 1,2,3
I thought slice(-3) would give me the last 3 elements of the array, but it seems I am missing something. Same problem happens when I am using filter(':gt(-4)').
Can someone explain me what I am doing wrong?
jQuery(document).ready(function() {
setTimeout(function () {
var prevs = jQuery('li').filter(':visible').first().prevAll();
var vis = jQuery('li').filter(':visible');
vis.hide(1000);
prevs.slice(-3).show(1000);
}, 1000);
});
li:nth-last-child(n+4) {
display: none
}
li {
width: 30px;
height: 30px;
border: 1px dotted gray;
background-color: red;
list-style: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
<li>1</li>
<li>2</li>
<li>3</li>
<li>4</li>
<li>5</li>
<li>6</li>
<li>7</li>
<li>8</li>
<li>9</li>
<li>10</li>
<li>11</li>
<li>12</li>
<li>13</li>
<li>14</li>
<li>15</li>
</ul>
The problem is var prevs = jQuery('li').filter(':visible').first().prevAll();, specifically, prevAll(). Per jquery documentation:
The .prevAll() method searches through the predecessors of these elements in the DOM tree and construct a new jQuery object from the matching elements; the elements are returned in order beginning with the closest sibling.
The array you get back are elements 0-11, but they are in the reverse order. So prevs[0] == 12. The last 3 elements are now 1, 2, and 3. To fix this, you need to reverse the array. Just wrap that right hand statement inside of Array.prototype.reverse.call(). Here is what you want I believe
jQuery(document).ready(function() {
setTimeout(function () {
var prevs = Array.prototype.reverse.call(jQuery('li').filter(':visible').first().prevAll());
var vis = jQuery('li').filter(':visible');
vis.hide(1000);
prevs.slice(-3).show(1000);
}, 1000);
});
li:nth-last-child(n+4) {
display: none
}
li {
width: 30px;
height: 30px;
border: 1px dotted gray;
background-color: red;
list-style: none;
}
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<ul>
<li>1</li>
<li>2</li>
<li>3</li>
<li>4</li>
<li>5</li>
<li>6</li>
<li>7</li>
<li>8</li>
<li>9</li>
<li>10</li>
<li>11</li>
<li>12</li>
<li>13</li>
<li>14</li>
<li>15</li>
</ul>
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