I'm working on an exercise where, starting from an array of arrays, I have to reduce it (using reduce and concat) in a single array that contains all the elements of every single arrays given.
So I start from this:
var array = [[1,2,3],[4,5,6],[7,8,9]]
And I solved the exercise with this:
var new_array = array.reduce(function(prev,cur){return prev.concat(cur);})
So it works, typing console.log(new_array) I have this:
[1, 2, 3, 4, 5, 6, 7, 8, 9]
But if I modify the function in this way:
var new_array = array.reduce(function(prev,cur){return prev.concat(cur);},0)
I get this error:
"TypeError: prev.concat is not a function
Why I get this error?
i not have completely clear how reduce works yet
It works like this:
Array.prototype.reduce = function(callback, startValue){
var initialized = arguments.length > 1,
accumulatedValue = startValue;
for(var i=0; i<this.length; ++i){
if(i in this){
if(initialized){
accumulatedValue = callback(accumulatedValue, this[i], i, this);
}else{
initialized = true;
accumulatedValue = this[i];
}
}
}
if(!initialized)
throw new TypeError("reduce of empty array with no initial value");
return accumulatedValue;
}
Your failing example does pretty much this:
var array = [[1,2,3],[4,5,6],[7,8,9]];
var tmp = 0;
//and that's where it fails.
//because `tmp` is 0 and 0 has no `concat` method
tmp = tmp.concat(array[0]);
tmp = tmp.concat(array[1]);
tmp = tmp.concat(array[2]);
var new_array = tmp;
replace the 0 with an Array, like [ 0 ]
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