Java Type Erasure Problem

Question

I've made an example to demonstrate my problem:

Metrical.java

public interface Metrical<T>
{
    double distance(T other);
}

Widget.java

public class Widget implements Metrical<Widget>
{
    private final double value;

    public Widget(double value) { this.value = value; }

    public double getValue() { return value; }

    public double distance(Widget other) { return Math.abs(getValue() - other.getValue()); }
}

Pair.java

public class Pair<T>
{
    private final double value;
    private final T object1, object2;

    public Pair(T object1, T object2, double value)
    {
        this.object1 = object1;
        this.object2 = object2;
        this.value = value;
    }

    public T getObject1() { return object1; }

    public T getObject2() { return object2; }

    public double getValue() { return value; }
}

Algorithm.java

import java.util.Set;

public class Algorithm<T extends Metrical<T>>
{
    public void compute(Set<T> objects)
    {

    }

    public void compute(Set<Pair<T>> pairs)
    {

    }
}

So, in Algorithm.java, Set< Pair< T >> is being seen as a Set< T > and thus I am having type erasure problems. However, is there any way I can get away with something like this without naming the methods differently? Both variants of the algorithm are meant to operate on T's, but I need to allow for different arguments. They compute the same thing, so in an effort to avoid confusion, I would rather not name them differently. Is there any way to accommodate this?

Answer 1

No there isn't.

You have to remember that someone could call your method with just a vanilla Set, in which case which one would be called?

That's why you can't do it. Just like you can't do:

interface A {
  void blah(Set set);
  void blah(Set<T> set);
}

Same problem.

The type information isn't available at runtime (ie type erasure).