Java: Regular expression to strip out: %j or %f

Question

Is there an easy way to strip out something like %j or %f out of a string and replace it with an int? like:

XYZ: %J Num: %f

becomes

XYZ: 12 Num: 34

Answer 1

A simple way would be:

"XYZ: %J Num: %f".replace("%J", "12").replace("%f", "34");

Answer 2

import java.util.Enumeration;
import java.util.Hashtable;

public class BasicReplace {

    public static void main(String[] args) {
        Hashtable<String, Integer> values = new Hashtable<String, Integer>();
       values.put("%J", 3);
       values.put("%F", 5);
       values.put("%E", 7);
        String inputStr = "XYZ: %J ABC: %F";
        String currentKey;
        Enumeration<String> enume = values.keys();
        while(enume.hasMoreElements()){
            currentKey = enume.nextElement();
            inputStr = inputStr.replaceAll(currentKey, String.valueOf(values.get(currentKey)));
        }
        System.out.println(inputStr);
        System.out.println("XYZ: %J Num: %f".replace("%J", "12").replace("%f", "34"));
    }
}

TUNDUN ! :D
Well, it might not exactly be "an easy way", but it works.