Java Function Overloading

Question

Can anyone tell me, why does "int" gets printed, as in the internal working.

class Test {

void Method(int i) {
    System.out.println("int");
}
void Method(String n) {
    System.out.println("string");
}

public static void main(String [] a) {
    new Test().Method('c');
    }

}

Answer 1

The character c is being cast to an int. It isn't going to be cast to a String.

More formally, from the JLS §5.5 - a widening conversion takes place from a char to an int, long, float, or double.

The reason that will never be seen as a String is that a char can't be autoboxed into a String.