iOS 16 SwiftUI List Background

Question

With the new SwiftUI update in iOS 16 List no longer depends on UITableView. So the following snippet we used to set the List background color to .clear is now useless:

UITableView.appearance().backgroundColor = .clear

I saw that someone used introspect to solve the problem, but does anyone know of another maybe cleaner way to achieve the same behavior?

Also note that on macOS, the following works fine (Tested using Xcode 14 beta & macOS Ventura):

extension NSTableView {
    open override func viewDidMoveToWindow() {
        super.viewDidMoveToWindow()
        backgroundColor = NSColor.clear
        enclosingScrollView!.drawsBackground = false
    }
}

Answer 1

iOS 16

Update: Xcode 14b3+

Just use new modifier:

    List {
        Text("Item 1")
        Text("Item 2")
        Text("Item 3")
    }
    .scrollContentBackground(Color.red)     // << here !!
//    .scrollContentBackground(Color.clear)     // << transparent !!
//    .scrollContentBackground(.hidden)     // << can be combined with above !!

Original

Now they use UICollectionView for backend, so an updated workaround is to change corresponding background colors:

Main part:

extension UICollectionReusableView {
    override open var backgroundColor: UIColor? {
        get { .clear }
        set { }

        // default separators use same color as background
        // so to have it same but new (say red) it can be
        // used as below, otherwise we just need custom separators
        // 
        // set { super.backgroundColor = .red }

    }
}

struct ContentView: View {
    init() {
        UICollectionView.appearance().backgroundColor = .clear
    }
//...

Test module on GitHub