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I have just installed xampp but I'm having problem inserting data into MySQL table. The data I inserted does not appear in phpmyadmin. I am not sure what is the problem.
Any help will be gratefully appreciated, here is my code:
<html>
<head>
<title>Test</title>
<body>
<form action="test.php" method="post">
Firstname: <input type="text" name="firstname" />
Lastname: <input type="text" name="lastname" />
Age: <input type="text" name="age" />
<input type="submit"name="submit" value="submit"/>
</form>
<?php
$host ="localhost";
$username = "***";
$password = "***";
$database = "***";
$table ="persons";
$con = mysql_connect("localhost","***","***");
if (!$con)
{
die('Could not connect: ' . mysql_error());
}
mysql_select_db("bucksbug_mesovot", $con);
$sql="INSERT INTO persons (firstname, lastname, age)
VALUES('$_POST[firstname]','$_POST[lastname]','$_POST[age]')";
if (!mysql_query($sql,$con))
{
die('Error: ' . mysql_error());
}
echo "Data inserted";
mysql_close($con);
?>
</body>
</html>
616
asked Aug 02 '26 04:08
Although you should really switch to PDO / mysqli and prepared statements with bound parameters to avoid sql injection and breaking sql statements if your variables contain quotation marks, you will probably run into problems with PDO / mysqli as well: Your password (change it!) contains a $.
See the following example on codepad:
<?php
function test($var)
{
echo $var;
}
$test_var = "test$string";
test($test_var);
Output:
test
You will not be able to connect successfully to the database as your password will never be correct.
Change:
"=c(p$zTTH2Jm"
to:
'=c(p$zTTH2Jm'
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