In Python, what's the method for returning only the max odd integer in a list?

Question

If you have a list of numbers, how do you return only the max odd integer without using the max() function?

I'm assuming it will have something to do with int % 2 != 0, but I'm not sure what else.

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I also have to return the overall max integer without using max(), but I got around that by sorting my list and using list[-1].

Answer 1

max(i for i in my_list if i % 2)

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Edit: without max():

def highest_odd(seq):
    """
    Return the highest odd number in `seq`.
    If there are no odd numbers, then return `None`.

    """
    for i in sorted(seq, reverse=True):
        if i % 2:
            return i