In Julia: How do I get the name of the currently running program?

Question

In Python 3.6+ the following works:

import sys
print(f"Program name is {sys.argv[0]}")
Program name is C:\Program Files\JetBrains\PyCharm Community Edition 2018.1\helpers\pydev\pydevconsole.py

How do I do this in Julia?

Answer 1

In a Julia program file, this works:

println("Program name is ", PROGRAM_FILE)

""" Output
Program name is StackQuestion.jl
"""

In the Julia 1.0 REPL there is no output:

julia> print("The program name is ", PROGRAM_FILE)
The program name is

This should not be a problem since getting the program name is something one would typically want to do within their running program.

A useful tip from the Julia 1.0 docs relating to the program file name is: https://docs.julialang.org/en/v1/manual/faq/#

"How do I check if the current file is being run as the main script?

When a file is run as the main script using julia file.jl one might want to activate extra functionality like command line argument handling. A way to determine that a file is run in this fashion is to check if abspath(PROGRAM_FILE) == @__FILE__ is true."