Is there any method? My computer is AMD64.
::std::string str; BOOL loadU(const wchar_t* lpszPathName, int flag = 0); When I used:
loadU(&str); the VS2005 compiler says:
Error 7 error C2664:: cannot convert parameter 1 from 'std::string *__w64 ' to 'const wchar_t *' How can I do it?
First convert it to std::wstring:
std::wstring widestr = std::wstring(str.begin(), str.end()); Then get the C string:
const wchar_t* widecstr = widestr.c_str(); This only works for ASCII strings, but it will not work if the underlying string is UTF-8 encoded. Using a conversion routine like MultiByteToWideChar() ensures that this scenario is handled properly.
If you have a std::wstring object, you can call c_str() on it to get a wchar_t*:
std::wstring name( L"Steve Nash" ); const wchar_t* szName = name.c_str(); Since you are operating on a narrow string, however, you would first need to widen it. There are various options here; one is to use Windows' built-in MultiByteToWideChar routine. That will give you an LPWSTR, which is equivalent to wchar_t*.
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