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How would one call std::forward on all arguments in a variadic function?

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What is std :: forward for?

std::forward If arg is an lvalue reference, the function returns arg without modifying its type. This is a helper function to allow perfect forwarding of arguments taken as rvalue references to deduced types, preserving any potential move semantics involved.

Can variadic methods take any number of parameters?

A variadic function allows you to accept any arbitrary number of arguments in a function.

What symbols are used in a function declaration to indicate that it is a variadic function?

A function with a parameter that is preceded with a set of ellipses ( ... ) is considered a variadic function. The ellipsis means that the parameter provided can be zero, one, or more values. For the fmt. Println package, it is stating that the parameter a is variadic.


You would do:

template <typename ...Params>
void f(Params&&... params)
{
    y(std::forward<Params>(params)...);
}

The ... pretty much says "take what's on the left, and for each template parameter, unpack it accordingly."


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