I'd like to plot a datafile using substrings from a column. My data file contains data in the format
1 (15, 3): dX: -1.619, dY: 3.315, dXSc: 0.981, dYSc: 0.993
2 ( 4,16): dX: -0.540, dY: -0.540, dXSc: 0.992, dYSc: 0.977
...
and I'd like to plot the numbers between the brackets (x,y) as y against x, something like:
plot "data.dat" u substr(($2),7,8 ):substr(($2),10,11)
What would be the correct syntax for this?
Doing this properly with gnuplot is a bit tricky, because gnuplot doesn't allow specifying an arbitrary format as input. Usually, the best way would be to use an external tool to extract the data for you and feed the resulting file to gnuplot (this could be also done on-the-fly using the syntax (plot '< script data.dat'...).
However, in your case there is a hack to get it working with gnuplot following the next steps:
set datafile separator ':' to have the information of both x and y in a single column.Use strstrt to determine the start and end string positions of the x and y values.
For the x-value this would be
substr(s, strstrt(s, "(")+1, strstrt(s, ",")-1)
Add 0.0 to the resulting substrings to have them implicitely converted to real values.
A complete script, which works with your example data is
set datafile separator ":"
get_x(c) = 0.0 + substr(strcol(c), strstrt(strcol(c), "(") + 1, strstrt(strcol(c), ",") - 1)
get_y(c) = 0.0 + substr(strcol(c), strstrt(strcol(c), ",") + 1, strstrt(strcol(c), ")") - 1)
plot 'data.dat' using (get_x(1)):(get_y(1)) with points pt 7 ps 2
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