How to use cut command in bash to show all columns except those indicated?

Question

I need to remove a column from a plain text file. I think this could be done using the inverse of the cut command. I mean, something like this:

If this is my file:

01 Procedimiento_tal retiro aceptado 01 tx1 01 tx2 01 tx3 02 Procedimiento_tal retiro rechazado 02 tx1 02 tx2 02 tx3 03 Procedimiento_tal retiro aceptado 03 tx1 03 tx2 03 tx3 

What can I do to remove the first column with cut and get the following text in bash?:

Procedimiento_tal retiro aceptado tx1 tx2 tx3 Procedimiento_tal retiro rechazado tx1 tx2 tx3 Procedimiento_tal retiro aceptado tx1 tx2 tx3 

Thanks in advance

Answer 1

Using cut:

cut -d ' ' -f 2- input-file 

should do what you want.

Answer 2

To read infile using ' ' as a delimiter (-d) and put fields (-f) 2 onwards (2-) into file:

cut -d' ' -f2- infile > file 

See man cut for more options.

N.B: This is not bash-specific.