How to use CreateFile API function for network path?

Question

I have come across the CreateFile API for C drive. It is working fine. But when I try to use a network share path it throws an error.

private void GetRootHandle()
    {
        string vol = string.Concat(@"\\192.168.1.24\share1");
        _changeJournalRootHandle = PInvokeWin32.CreateFile(vol,
             PInvokeWin32.GENERIC_READ | PInvokeWin32.GENERIC_WRITE,
             PInvokeWin32.FILE_SHARE_READ | PInvokeWin32.FILE_SHARE_WRITE,
             IntPtr.Zero,
             PInvokeWin32.OPEN_EXISTING,
             0,
             IntPtr.Zero);
        if (_changeJournalRootHandle.ToInt32() == PInvokeWin32.INVALID_HANDLE_VALUE)
        {
            throw new IOException("CreateFile() returned invalid handle",
                new Win32Exception(Marshal.GetLastWin32Error()));
        }
    }

Can any one give me an idea how to use share path for this API function

Answer 1

I am getting Access is denied exception

That's because it is not a file. Get ahead by not using CreateFile(), it just isn't necessary. Use the regular .NET classes, like DirectoryInfo.EnumerateFiles() to enumerate files, FileStream to open them. Use the FileStream.SafeFileHandle property if you need to pinvoke GetFileInformationByHandle().