I've two tables one is car_category having the fields - id,type. Another table named vehicle having field - c_id(FK Refers car - id). Now I want to display the FK(c_id) value which is car-type. I've below code in models,
class Car extends Model
{
protected $guarded = [];
protected $table = 'car_category';
public function vehicles()
{
return $this->hasMany('Vehicle');
}
}
vehicle model,
class Vehicle extends Model
{
protected $guarded = [];
protected $table = 'vehicles';
public function cars()
{
return $this->belongsTo('Car');
}
}
What 'll be my query for this? I've tried this code, results error.
$vehicles = "SELECT cars.cartype,vehicles.model FROM cars,vehicles
WHERE cars.id = vehicles.c_id";
How can I achieve this? Can anybody help me?
Try this
class Car extends Model
{
protected $guarded = [];
protected $table = 'car_category';
public function vehicles()
{
return $this->hasMany(Vehicle::class, 'c_id');
}
}
The vehicle model
class Vehicle extends Model
{
protected $guarded = [];
protected $table = 'vehicles';
public function cars()
{
return $this->belongsTo(Car::class, 'c_id');
}
}
Eloquent determines the foreign key of the relationship based on the model name. In this case, the Car model is automatically assumed to have a car_id foreign key. If you wish to override this convention, you may pass a second argument to the method
https://laravel.com/docs/5.5/eloquent-relationships#one-to-one
To get the Car along with their Vehicle information you can do a query using Eager Loading
$result = Car::with('vehicles')->get();
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