Please consider this df:
df = pd.DataFrame({'a':[1,2], 'b':[1,2], 'c':[1,2], 'd':[1,2], 'e':[1,2], 'f':[1,2], 'g':[1,2], 'h':[1,2]})
a b c d e f g h
0 1 1 1 1 1 1 1 1
1 2 2 2 2 2 2 2 2
How can I select the 1st, 4th, and 5th-7th columns? What I tried:
df.iloc[:, [0, 3, np.arange(5,8)]]
ValueError: setting an array element with a sequence.
You can do this:
df.iloc[:, [0, 3] + list(range(5,8))]
[0, 3] + list(range(5,8)) concatenates 2 lists, combining your explicit list with a list derived from your desired range.
Alternatively, you can use numpy.r to build an indexing array for you:
import numpy as np
df.iloc[:, np.r_[0,3,5:8]]
np.r_[0,3,5:8] # array([0, 3, 5, 6, 7])
This would be useful, for example, if you have multiple ranges.
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