How to remove last odd number in a list

Question

I have a list of numbers and I would like to remove the LAST odd number from it. This code works well only when the last odd number is not repeated throughout the list before:

numbers = [1, 7, 2, 34, 8, 7, 2, 5, 14, 22, 93, 48, 76, 15, 7]
odd_numbers = []

def remove_last_odd(numbers):
    for n in numbers:
        if n % 2 != 0:
            odd_numbers.append(n)    
    numbers.remove(odd_numbers[-1])
    return numbers

So instead of removing the last 7, I end up removing the first occurrence of 7 in my "numbers" list.

Can anyone help?

Answer 1

not the most efficient way but will work:

def remove_last_odd(numbers):
    rnumbers = numbers[::-1]
    for n in rnumbers:
        if n % 2 != 0:  
            rnumbers.remove(n)
            break
    return rnumbers[::-1]

basically do this: reverse list, remove first odd number, reverse again and return.

Answer 2

This happens because the loop iterates from first element to last element. Just reverse loop:

for n in reversed(numbers):