I have an array of objects (or just numbers), and I have another array which contains all the objects that should not be removed from the first array in any circumstances. It looks something like this:
-- Array of objects (just numbers for now)
Objects = {}
-- Array of objects that should always stay in the 'Objects' array
DontDestroyThese = {}
-- Populate the arrays
Objects[#Objects+1] = 1
Objects[#Objects+1] = 2
Objects[#Objects+1] = 3
Objects[#Objects+1] = 4
Objects[#Objects+1] = 5
DontDestroyThese[#DontDestroyThese+1] = 2
DontDestroyThese[#DontDestroyThese+1] = 5
Now, I have a method called destroy() that should remove all objects from the Objects array except those included in the DontDestroyThese array. The method looks something like this:
function destroy()
for I = 1, #Objects do
if(DontDestroyThese[Objects[I]] ~= nil) then
print("Skipping " .. Objects[I])
else
Objects[I] = nil
end
end
end
However, as the result, the Objects array now contains nil values here and there. I'd like to remove these nils so that the Objects array would consist only of the numbers that were left there after calling destroy(). How do I do that?
I think the solution is much simpler. To remove any nils ('holes' in your array), all you need to do is iterate your table using pairs(). This will skip over any nils returning only the non-nil values that you add to a new local table that is returned in the end of the 'cleanup' function. Arrays (tables with indices from 1..n) will remain with the same order. For example:
function CleanNils(t)
local ans = {}
for _,v in pairs(t) do
ans[ #ans+1 ] = v
end
return ans
end
Then you simply need to do this:
Objects = CleanNils(Objects)
To test it:
function show(t)
for _,v in ipairs(t) do
print(v)
end
print(('='):rep(20))
end
t = {'a','b','c','d','e','f'}
t[4] = nil --create a 'hole' at 'd'
show(t) --> a b c
t = CleanNils(t) --remove the 'hole'
show(t) --> a b c e f
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