How to produce range with step in Perl

Question

In Bash, seq 5 5 20 produces 5 10 15 20.

In Perl, 1..5 produces 1 2 3 4 5; does it support step?

How do I produce a range with step in Perl?

Answer 1

perldoc -f map is one way:

use warnings; use strict; use Data::Dumper;  my @ns = map { 5 * $_ } 1 .. 4; print Dumper(\@ns);  __END__  $VAR1 = [           5,           10,           15,           20         ]; 

See also: perldoc perlop

Answer 2

The range operator in Perl doesn't support steps. You could use a for loop instead:

for (my $i = 5; $i <= 20; $i += 5) {     print "$i\n"; }