how can i print a char array such i initialize and then concatenate to another char array? Please see code below
int main () {
char dest[1020];
char source[7]="baby";
cout <<"source: " <<source <<endl;
cout <<"return value: "<<strcat(dest, source) <<endl;
cout << "pointer pass: "<<dest <<endl;
return 0;
}
this is the output
source: baby
return value: v����baby
pointer pass: v����baby
basically i would like to see the output print
source: baby
return value: baby
pointer pass: baby
printf(char *format, arg1, arg2, …) This function prints the character on standard output and returns the number of character printed, the format is a string starting with % and ends with conversion character (like c, i, f, d, etc.).
using printf() If we want to do a string output in C stored in memory and we want to output it as it is, then we can use the printf() function. This function, like scanf() uses the access specifier %s to output strings. The complete syntax for this method is: printf("%s", char *s);
You haven't initialized dest
char dest[1020] = ""; //should fix it
You were just lucky that it so happened that the 6th (random) value in dest was 0. If it was the 1000th character, your return value would be much longer. If it were greater than 1024 then you'd get undefined behavior.
Strings as char arrays must be delimited with 0. Otherwise there's no telling where they end. You could alternatively say that the string ends at its zeroth character by explicitly setting it to 0;
char dest[1020];
dest[0] = 0;
Or you could initialize your whole array with 0's
char dest[1024] = {};
And since your question is tagged C++ I cannot but note that in C++ we use std::strings which save you from a lot of headache. Operator + can be used to concatenate two std::strings
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