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How to pass parameters to a javascript function on onclick?

I have a script where i want to call another function on onclick by passing parameters.I want to call remove_product function .How can i achieve this?

function load_cart(){
$('.mini-cart-products').html('');
var url = $('.ajax-url').attr('href');
var t   = 0;
// console.log(url);
$.ajax({
    url     : url,
    dataType:'json',
    success:function(result){

        if(result.length > 0)
        {
            var image       = $('.mini-cart-image a img');
            var prod_name   = $('.mini-cart-name a');
            var attribute   = $('.mini-cart-attributes');
            var pricing     = $('.mini-cart-pricing');

            $.each(result, function(key, val){

                var remove_url = val.remove;
                var barcode = val.barcode;
                var cart_id = val.cart_id;
                console.log("remove_url :"+remove_url+" barcode : "+barcode+" cart_id : "+cart_id);
                var productDiv  = $( "<div class='mini-cart-product clearfix'></div>" );                                             
                var nameDiv     = '<div class="mini-cart-name font"><a href="'+val.link+'">'+val.name+'</a></div>';
                var attributes  = $( "<div class='mini-cart-attributes'></div>" );
                var colorAttr   = '<div class="attribute"><span class="label">Colour: </span><span class="value">'+val.color+'</span></div>';
                var sizeAttr    = '<div class="attribute"><span class="label">Size&nbsp&nbsp&nbsp: </span><span class="value">'+val.size+'</span></div>';
                var remove  = '<div class="mini-cart-remove"><a onclick="remove_product(remove_url,barcode,cart_id)">Remove</a></div>';
like image 259
piya Avatar asked Oct 30 '25 04:10

piya


1 Answers

The line of remove var should be something like that.

var remove  = '<div class="mini-cart-remove"><a onclick="remove_product(\''+remove_url+'\',\''+barcode+'\',\''+cart_id+'\')">Remove</a></div>';

This will solve your problem

Sample fiddle

like image 111
Shailendra Sharma Avatar answered Oct 31 '25 18:10

Shailendra Sharma



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