How to pass CSV file as an argument to python file

Question

I am trying to supply csv file as an argument in python file, Here, I want to pass features.csv file as an argument. Any thoughts how to make it?

def read_csv_file():
with open(r'features.csv', 'r') as csvFile:
    checker = lambda i: bool(i and i.strip())
    raw_file = csv.reader(csvFile)
    header = next(raw_file)
    folders = next(
        {
            header[0]: [row[0]],
            'Feature Name': list(filter(checker, row[:1])),
            'Child folder': list(filter(checker, row[1:]))
        } for row in raw_file
    )
    raw_folder_list = list(folders.values())
    folder_list = sum(raw_folder_list, [])
    return folder_list

Answer 1

I think you are trying to make filename a command line argument so that, you can reuse this code to open all similar csv files.

In that case, you can use argparse

or, simply

>> python read_csv.py filename.csv

In read_csv.py

import sys
first_arg = sys.argv[1]
print(first_arg)
# filename.csv

I would recommend using argparse since it is more robust.