if I have this url: node/95/pdf/1. How will I able to get the numeric/value 1? Tried the parse_url but gave me the wrong output.
PS: the value 1 is just an example, the id is dynamic depends on what the user click.
I would use sscanf
Untested example:
list($node_id, $pdf_id) = sscanf($url, "node/%d/pdf/%d");
$node_id contains the node id, $pdf_id contains the pdf id. According to your comment: Yes, you can output it with e.g. echo $pdf_id;.
If you need them both in an array, you can remove the list() method, doing it like this:
$ids = sscanf($url, "node/%d/pdf/%d");.
This returns an array with both node and pdf id in $ids.
Finally, if you just need the pdf id, you could do
$id = sscanf($url, "node/95/pdf/%d");.
I just showed how to fetch both because I assumed you may need both numbers from your url.
Edit
seeing all the other answers after posting my solution, I am wondering why everyone is solving this with multiple functions when there is a function available that does exactly what he needs: parsing a string according to a format. This also leads to less sql-injection prone code IMHO. And it doesn't break something when the url gets extended or query strings are appended.
Edit 2
list($node_id, $sub, $sub_id) = sscanf($url, "node/%d/%[^/]/%d"); will get you the "pdf" and it's id separate instead of "node/%d/%s/%d". This is because char / is also matched by %s. Using %[^/] matches everything except the forward slash.
You can do this:
$id = end(explode('/', 'node/95/pdf/1'));
Example:
$arr = explode('/', 'node/95/pdf/1');
$id = end($arr);
echo $id; // 1
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