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How to parse a ping result with regex

What I want is to parse the result of a ping, line by line. It's a bit tricky for me and tried a lot of things but well... I'm using the ping on Android.

For example:

PING google.com (173.194.35.9) 56(84) bytes of data.
64 bytes from mil01s16-in-f9.1e100.net (173.194.35.9): icmp_seq=1 ttl=52 time=33.0 ms

--- google.com ping statistics ---
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 33.086/33.086/33.086/0.000 ms

On the first line, I want the Ip address, the "56(84) bytes of data". On second line "64 bytes", 1,52,33.0 ms etc.

If a ping an IP directly, it changes a little bit

PING 192.168.0.12 (192.168.0.12) 56(84) bytes of data.
64 bytes from 192.168.0.12: icmp_seq=1 ttl=64 time=0.134 ms

--- 192.168.0.12 ping statistics ---
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 0.134/0.134/0.134/0.000 ms

But should work too !

And if I have a little explaination with an answer, it would be cool !

Thanks so much!

like image 373
brunettia Avatar asked Oct 23 '25 14:10

brunettia


1 Answers

Description

This expression will capture IP, bytes of data, bytes, ICMP_SEQ, ttl, time. I couldn't find etc.

^PING\b # match ping
[^(]*\(([^)]*)\) # capture IP
\s([^.]*)\. # capture the bytes of data
.*?^(\d+\sbytes)  # capture bytes
.*?icmp_seq=(\d+)  # capture icmp_seq
.*?ttl=(\d+)  # capture ttl
.*?time=(.*?ms)  # capture time
.*?(\d+)\spackets\stransmitted   # the rest of these lines will capture the other portions of the ping result
.*?(\d+)\sreceived
.*?(\d+%)\spacket\sloss
.*?time\s(\d+ms)
.*?=\s([^\/]*)\/([^\/]*)\/([^\/]*)\/(.*)\sms

enter image description here

Example

Live Example: http://www.rubular.com/r/uEDoEZwY7U

Sample Text

PING google.com (173.194.35.9) 56(84) bytes of data.
64 bytes from mil01s16-in-f9.1e100.net (173.194.35.9): icmp_seq=1 ttl=52 time=33.0 ms

--- google.com ping statistics ---
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 33.086/33.086/33.086/0.000 ms


PING 192.168.0.12 (192.168.0.12) 56(84) bytes of data.
64 bytes from 192.168.0.12: icmp_seq=1 ttl=64 time=0.134 ms

--- 192.168.0.12 ping statistics ---
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 0.134/0.134/0.134/0.000 ms

Sample Code

import java.util.regex.Pattern;
import java.util.regex.Matcher;
class Module1{
  public static void main(String[] asd){
  String sourcestring = "source string to match with pattern";
  Pattern re = Pattern.compile("^PING\\b # match ping
[^(]*\\(([^)]*)\\) # capture IP
\\s([^.]*)\\. # capture the bytes of data
.*?^(\\d+\\sbytes) # capture bytes
.*?icmp_seq=(\\d+) # capture icmp_seq
.*?ttl=(\\d+) # capture ttl
.*?time=(.*?ms) # capture time
.*?(\\d+)\\spackets\\stransmitted
.*?(\\d+)\\sreceived
.*?(\\d+%)\\spacket\\sloss
.*?time\\s(\\d+ms)
.*?=\\s([^\\/]*)\\/([^\\/]*)\\/([^\\/]*)\\/(.*?)\\sms


",Pattern.CASE_INSENSITIVE | Pattern.MULTILINE | Pattern.DOTALL);
  Matcher m = re.matcher(sourcestring);
  int mIdx = 0;
    while (m.find()){
      for( int groupIdx = 0; groupIdx < m.groupCount()+1; groupIdx++ ){
        System.out.println( "[" + mIdx + "][" + groupIdx + "] = " + m.group(groupIdx));
      }
      mIdx++;
    }
  }
}

Capture Groups

[0][0] = PING google.com (173.194.35.9) 56(84) bytes of data.
64 bytes from mil01s16-in-f9.1e100.net (173.194.35.9): icmp_seq=1 ttl=52 time=33.0 ms

--- google.com ping statistics ---
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 33.086/33.086/33.086/0.000 ms
[0][2] = 173.194.35.9
[0][2] = 56(84) bytes of data
[0][3] = 64 bytes
[0][4] = 1
[0][5] = 52
[0][6] = 33.0 ms
[0][7] = 1
[0][8] = 1
[0][9] = 0%
[0][10] = 0ms
[0][11] = 33.086
[0][12] = 33.086
[0][13] = 33.086
[0][14] = 0.000


[1][0] = PING 192.168.0.12 (192.168.0.12) 56(84) bytes of data.
64 bytes from 192.168.0.12: icmp_seq=1 ttl=64 time=0.134 ms

--- 192.168.0.12 ping statistics ---
1 packets transmitted, 1 received, 0% packet loss, time 0ms
rtt min/avg/max/mdev = 0.134/0.134/0.134/0.000 ms
[1][3] = 192.168.0.12
[1][2] = 56(84) bytes of data
[1][3] = 64 bytes
[1][4] = 1
[1][5] = 64
[1][6] = 0.134 ms
[1][7] = 1
[1][8] = 1
[1][9] = 0%
[1][10] = 0ms
[1][11] = 0.134
[1][12] = 0.134
[1][13] = 0.134
[1][14] = 0.000
like image 98
Ro Yo Mi Avatar answered Oct 26 '25 03:10

Ro Yo Mi



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