How to move first column to last column in unix?

Question

This is the data in a text file.

0.354167 male atyp_angina 0.066038 0.1621 t normal 0.648855 no 0 up 0 reversable_defect <50
0.625 male typ_angina 0.792453 0.328767 f left_vent_hyper 0.564885 no 0.677419 down 0 reversable_defect <50
0.645833 male non_anginal 0.433962 0.134703 f left_vent_hyper 0.641221 no 0.483871 flat 0 normal >50_1
0.666667 female asympt 0.481132 0.413242 f left_vent_hyper 0.572519 yes 0.16129 flat 0 reversable_defect >50_1
0.270833 male typ_angina 0.509434 0.269406 f left_vent_hyper 0.816794 no 0.129032 up 0.666667 normal <50

I have to move first column contains numeric data to the last column for every row.

For eg:

0.354167 male atyp_angina 0.066038 0.1621 t normal 0.648855 no 0 up 0 reversable_defect <50

TO

male atyp_angina 0.066038 0.1621 t normal 0.648855 no 0 up 0 reversable_defect <50 0.354167

How can I do using bash commands?

Answer 1

Short awk solution (without loop though all fields):

awk '{ $(NF+1)=$1; sub(/^[^ ]+ */,"") }1' file.txt

• $(NF+1)=$1 - append the 1st field to the end (as the last field)

• sub(/^[^ ]+ */,"") - remove the 1st field with following space(s)

---

The output:

male atyp_angina 0.066038 0.1621 t normal 0.648855 no 0 up 0 reversable_defect <50 0.354167
male typ_angina 0.792453 0.328767 f left_vent_hyper 0.564885 no 0.677419 down 0 reversable_defect <50 0.625
male non_anginal 0.433962 0.134703 f left_vent_hyper 0.641221 no 0.483871 flat 0 normal >50_1 0.645833
female asympt 0.481132 0.413242 f left_vent_hyper 0.572519 yes 0.16129 flat 0 reversable_defect >50_1 0.666667
male typ_angina 0.509434 0.269406 f left_vent_hyper 0.816794 no 0.129032 up 0.666667 normal <50 0.270833

Answer 2

Perl is handy for text manipulation:

perl -lane 'push @F, shift @F; print "@F"' file