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How to get all elements that are highlighted

Tags:

javascript

dom

I want to get all of the elements in a user highlighted area. The problem is that I don't know how to traverse to different parts of the DOM, when the elements are on a different part of the tree. My code so far can only get the elements off the startContainer of the selection range. Do I need some sort of recursion? Here is my code:

    getSelectedElementTags:function() 
{
    var range, sel, container;
    sel = content.window.getSelection();
    if (sel.getRangeAt) 
    {
        if (sel.rangeCount > 0) 
        {
            range = sel.getRangeAt(0);              
        }
    } 
    else 
    {       
        range = content.window.createRange();
        range.setStart(sel.anchorNode, sel.anchorOffset);
        range.setEnd(sel.focusNode, sel.focusOffset);
        alert("range created");
    }


    if (range)
    {
        container = range["startContainer"];
        var elms = container.parentNode.getElementsByTagName("*");          
        elmlist = "parent: "+container.parentNode.tagName + " (" + elms.length + ")\n";
        for (i in elms)
        {
            if (elms[i].tagName != null)
            {
                elmlist += elms[i].tagName+"\n";
            }
        }

        alert(elmlist);
    }
},
like image 453
John Sheares Avatar asked Dec 02 '22 07:12

John Sheares


1 Answers

You could use a TreeWalker using document.createTreeWalker. An example is below. It lists all elements that are partially or fully selected. You can easily change the behaviour by modifying the parameters passed to document.createTreeWalker.

Note that in Firefox you don't need to check for the existence of the getRangeAt method of a selection. This check is only required for older versions of WebKit. Also, IE < 9 does not support TreeWalker or Range, so the following won't work in those browsers.

Edit Fixed as per comments below.

function rangeIntersectsNode(range, node) {
    var nodeRange;
    if (range.intersectsNode) {
        return range.intersectsNode(node);
    } else {
        nodeRange = node.ownerDocument.createRange();
        try {
            nodeRange.selectNode(node);
        } catch (e) {
            nodeRange.selectNodeContents(node);
        }

        return range.compareBoundaryPoints(Range.END_TO_START, nodeRange) == -1 &&
            range.compareBoundaryPoints(Range.START_TO_END, nodeRange) == 1;
    }
}

function getSelectedElementTags(win) {
    var range, sel, elmlist, treeWalker, containerElement;
    sel = win.getSelection();
    if (sel.rangeCount > 0) {
        range = sel.getRangeAt(0);
    }

    if (range) {
        containerElement = range.commonAncestorContainer;
        if (containerElement.nodeType != 1) {
            containerElement = containerElement.parentNode;
        }

        treeWalker = win.document.createTreeWalker(
            containerElement,
            NodeFilter.SHOW_ELEMENT,
            function(node) { return rangeIntersectsNode(range, node) ? NodeFilter.FILTER_ACCEPT : NodeFilter.FILTER_REJECT; },
            false
        );

        elmlist = [treeWalker.currentNode];
        while (treeWalker.nextNode()) {
            elmlist.push(treeWalker.currentNode);
        }

        console.log(elmlist);
    }
}

<input type="button" onclick="getSelectedElementTags(window)" value="Get selected elements">
like image 195
Tim Down Avatar answered Dec 04 '22 06:12

Tim Down