How to explain "$1,$2" in JavaScript when using regular expression?

Question

A piece of JavaScript code is as follows:

num = "11222333"; re = /(\d+)(\d{3})/; re.test(num); num.replace(re, "$1,$2"); 

I could not understand the grammar of "$1,$2". The book from which this code comes says $1 means RegExp.$1, $2 means RegExp.$2. But these explanations lead to more questions:

1. It is known that in JavaScript, the name of variables should begin with letter or _, how can $1 be a valid name of member variable of RegExp here?

2. If I input $1, the command line says it is not defined; if I input "$1", the command line only echoes $1, not 11222. So, how does the replace method know what "$1,$2" mean?

Thank you.

Answer 1

It's not a "variable" - it's a placeholder that is used in the .replace() call. $n represents the nth capture group of the regular expression.

var num = "11222333";  // This regex captures the last 3 digits as capture group #2 // and all preceding digits as capture group #1 var re = /(\d+)(\d{3})/;  console.log(re.test(num));  // This replace call replaces the match of the regex (which happens // to match everything) with the first capture group ($1) followed by // a comma, followed by the second capture group ($2) console.log(num.replace(re, "$1,$2"));

Answer 2

$1 is the first group from your regular expression, $2 is the second. Groups are defined by brackets, so your first group ($1) is whatever is matched by (\d+). You'll need to do some reading up on regular expressions to understand what that matches.

It is known that in Javascript, the name of variables should begin with letter or _, how can $1 be a valid name of member variable of RegExp here?

This isn't true. $ is a valid variable name as is $1. You can find this out just by trying it. See jQuery and numerous other frameworks.