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How to escape unicode string for regular expressions?

I need to build an re pattern based on the unicode string (e.g. I have "word", and I need something like ^"word"| "word"). However the "word" can contain special re characters. To match the "word" as it is, I need to escape special re characters in unicode string. The basic re.escape() function does the job for ascii strings. How can I do this for unicode?

like image 248
Chen Gupta Avatar asked May 26 '26 09:05

Chen Gupta


1 Answers

re.escape() inserts a backslash before every character that's not an ASCII alphanumeric. This may in fact lead to a multitude of unnecessary backslashes to be inserted, however, Python ignores backslashes that don't start a recognized escape sequence, so there is no big harm done (except possibly some performance penalty).

But if you want to build a stricter escape(), you can:

def escape(s):
    return re.sub(r"[(){}\[\].*?|^$\\+-]", r"\\\g<0>", s)

which only touches the actual regex metacharacters. I sure hope I didn't miss any :)

like image 154
Tim Pietzcker Avatar answered May 27 '26 22:05

Tim Pietzcker



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