How to do basename on second field in a file and replace it in line

Question

I'm trying to get something like basename of second field in a file and replace it:

$ myfile=/var/lib/jenkins/myjob/myfile

$ sha512sum "$myfile" | tee myfile-checksum
$ cat myfile-checksum
deb32b1c7122fc750a6742765e0e54a821 /var/lib/jenkins/myjob/myfile

Desired output:

deb32b1c7122fc750a6742765e0e54a821 myfile

So people can easily do sha512sum -c myfile-checksum with no manual edits.

With sed or awk, that is how far i made it for now :)

awk -F/ '{print $NF}' myfile-checksum
sed -i "s|${value}|$(basename $value)|" myfile-checksum

Thanks.

Answer 1

You can set the field separators to both spaces and slashes and print the first and last fields:

awk -F" |/" '{print $1, $NF}'

With your input:

$ awk -F" |/" '{print $1, $NF}' <<< "deb32b1c7122fc750a6742765e0e54a821 /var/lib/jenkins/myjob/myfile"
deb32b1c7122fc750a6742765e0e54a821 myfile

In case your filename contain spaces, do remove everything from the first field up to the last slash, as indicated by Ed Morton:

$ awk '{hash=$1; gsub(/^.*\//,""); print hash, $0}' <<< "deb32b1c7122fc750a6742765e0e54a821 /var/lib/jenkins/myjob/myfile with spaces"
deb32b1c7122fc750a6742765e0e54a821 myfile with spaces