How to do a generic call to function based on a Type object? [duplicate]

Question

how do you execute Get, when all you have is: T expressed as a Type object i.e.

Type type=typeof(int);

and arguments param1 and param2?

    public void DoCall(){
        var type=typeof(int);
        // object o=Get<type> ("p1","p2");   //<-- wont work (expected)
        // *** what should go here? ***
    }

    public IEnumerable<T> Get<T>(string param1,string param2) {
        throw new NotImplementedException();
    }

Answer 1

You need to use reflection:

public IEnumerable GetBoxed(Type type, string param1, string param2)
{
    return (IEnumerable)this
        .GetType()
        .GetMethod("Get")
        .MakeGenericMethod(type)
        .Invoke(this, new[] { param1, param2 });
}

Answer 2

MakeGenericMethod is the key:

var get = typeof(WhereverYourGetMethodIs).GetMethod("Get");
var genericGet = get.MakeGenericMethod(type);