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How to detect audio retakes using Python?

I have a lot of audio recordings for lectures where I say the same thing multiple times, mostly it's incomplete statements like:

"this is the part" (and then retrying)

"this is the part where" (and then retrying)

"this is the part where we will explore the theory"

Visually in any audio or video editor, I can spot these as the waveforms look very similar i.e. the same type of high low points on the waveform.

So I am trying to use Python to do the same, so that I only keep the last retake but silence the older ones, so the audio length doesn't change. Right now my approach is like this but it gives me the exact same audio as the input.

import librosa
import numpy as np
import soundfile as sf
import os

# Load the audio file
file_path = r'C:\test.wav'
y, sr = librosa.load(file_path, sr=None)

# Parameters
chunk_duration = 1  # seconds
overlap = 0.75  # 75% overlap for better similarity matching
chunk_length = int(chunk_duration * sr)
step_length = int(chunk_length * (1 - overlap))

# List to store the indices of the last occurrence of each chunk
last_occurrence_end = 0

# Create a list to store the final audio chunks
final_audio = []

# Loop over the audio in chunks
i = 0
while i < len(y) - chunk_length:
    chunk = y[i:i + chunk_length]
    next_chunk_start = i + step_length
    
    # If this is the last chunk, just keep it
    if next_chunk_start + chunk_length > len(y):
        last_occurrence_end = len(y)
        break

    next_chunk = y[next_chunk_start:next_chunk_start + chunk_length]
    
    # Compute simple Euclidean distance between the two chunks
    distance = np.linalg.norm(chunk - next_chunk)
    
    # Set a threshold for similarity
    if distance > 1000:  # Adjust this threshold as needed
        if i > last_occurrence_end:
            final_audio.append(y[last_occurrence_end:i])
        last_occurrence_end = i + chunk_length
    
    i = next_chunk_start

# Append the last segment after the loop
if last_occurrence_end < len(y):
    final_audio.append(y[last_occurrence_end:])

# Check if any chunks were added to final_audio
if final_audio:
    # Concatenate all the kept chunks to form the final trimmed audio
    final_audio = np.concatenate(final_audio)
else:
    # If no chunks were kept, return the original audio
    final_audio = y

# Define the new file path with "_clean" suffix
new_file_path = os.path.splitext(file_path)[0] + '_clean.wav'

# Export the trimmed audio
sf.write(new_file_path, final_audio, sr)

print(f"Cleaned audio saved as: {new_file_path}")
like image 574
Joan Venge Avatar asked Aug 06 '26 04:08

Joan Venge


1 Answers

NOTE: There might be solutions that require less work, using speech recognition or ready-to-use packages that do what you need.

If I was to do this by my own, for fun, I would try such idea:

  1. Find beginnings (1-2 seconds?) of utterings. I assume each sentence is separable because of some silent pause. If not this point might need re-thinking.
  2. Turn those signals into vectors of features. Most common is STFT + MFCC combo (scipy.signal.stft, librosa.feature.mfcc)
  3. Calculate distance matrix between vectors of features of consecutive sentences.
  4. Use dynamic time warping (DTW) algorithm (https://github.com/pollen-robotics/dtw) to analyse those distance matrices. You may want to search for long almost diagonal lines, that run through low-distance "pixels".

DTW algorithm presentation

You may need to add some normalization to distances. For sure - add more weight to distances of high energy frames (so some irrelevant silent frames do not noise DTW).

like image 58
dankal444 Avatar answered Aug 08 '26 17:08

dankal444



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