How to create random number within bounds in Java displayed as a binary value?

Question

I am able to generate Random Numbers with Random method. But I want to create random numbers that are displayed in a binary format. The numbers must be within a specific range.

Random numbers should be between 5 and 10 digits, inclusive.

E.g.: 011110, 0111100, 010110101.

Answer 1

Try the Following Code Snippet (Random number generation from This Stack Overflow question)

import java.util.Random;

public class Main {
    private static Random random = new Random();
    private static final int MAX = 1023;
    private static final int MIN = 16;

    public static void main(String[] args) {
        Integer randInt = random.nextInt((MAX - MIN) + 1) + MIN;
        System.out.println("random binary is: " + Integer.toBinaryString(randInt));
    }
}

MIN of 16 enforces a minimum of 5 binary digits where:

10000 is equal to 16

MAX of 1023 enforces a max of 10 binary digits where:

111111111 equal to 1023

The Utility method Integer.toBinaryString(int) converts the Integer into a binary readable format (enforcing the only '1's and '0's condition)

Answer 2

private Set set = new LinkedHashSet();
private Random rand = new Random();
public String getNo(){
    int range = getRandom(5, 10);        
    StringBuffer nu = new StringBuffer();
    for(int i=0,length=range;i<length;i++){
        nu.append(getRandom(0, 1));
    }
    String nuString = nu.toString();
    if(set.contains(nuString)){
        return getNo();
    }
    set.add(nuString);
    return nuString;
}

public int getRandom(int min, int max) {            
    return rand.nextInt((max - min) + 1) + min;
}