How to create byte array with your own bytes?

Question

I have to create my own byte array e.g:

byte[] connect = new byte[] { 0x00, 0x21, 0x60, 0x1F, 0xA1, 0x07 };

This byte array works fine, but I need to change some hex code. I tried to do a lot of changes but no one work.

Int32 hex = 0xA1; 

byte[] connect = new byte[] { 0x00, 0x21, 0x60, 0x1F, 0xA1, hex};


string hex = "0xA1"; 

byte[] connect = new byte[] { 0x00, 0x21, 0x60, 0x1F, 0xA1, hex};


byte[] array = new byte[1];
array[0] = 0xA1;

byte[] connect = new byte[] { 0x00, 0x21, 0x60, 0x1F, 0xA1, array[0]};

I don't know what type of variable I must have to use to replace automatic the array values.

Answer 1

Cast your int to byte:

Int32 hex = 0xA1; 
byte[] connect = new byte[] { 0x00, 0x21, 0x60, 0x1F, 0xA1, (byte)hex};

Or define it as byte to begin with:

byte hex = 0xA1; 
byte[] connect = new byte[] { 0x00, 0x21, 0x60, 0x1F, 0xA1, hex};

String to byte conversion:

static byte hexstr2byte(string s)
{
    if (!s.StartsWith("0x") || s.Length != 4)
        throw new FormatException();
    return byte.Parse(s.Substring(2), System.Globalization.NumberStyles.HexNumber);
}

As you can see, .NET formatting supports hexa digits, but not the "0x" prefix. It would be easier to omit that part altogether, but your question isn't exactly clear about that.