How to Both Pass an Argument Into a Function and Get a Return Value in Bash? [duplicate]

Question

My code is very simple.

variable=$( createTable $table_name )

or

returnedVariable=$( function $argument )

My code breaks on this line. I haven't been able to find anywhere on the internet how to both pass an argument and get a return value in Bash.

UPDATE: I get it now. I can't have multiple echo's in my function. Also echo should never be considered a return but a print statement or stdout which you can capture. Thank you for the feedback!

Answer 1

is this what you're trying to do?

$ function createTable() { echo "this is the table: $1"; }    
$ var=$(createTable "$table_name")
$ echo "$var"
this is the table: New Table

note that there is nothing returned from the function, that's reserved for the success/error status. Here will default to zero. The conceptual "function return value" is through the stdout. These are not "functions" in mathematical sense.