How does IEnumerable .Min handle Nullable types?

Question

So, IEnumerable uses the IComparable interface to evaluation a call to .Min(). I'm having trouble finding whether or not the nullable types support this. Assuming I have a list of int?, {null, 1, 2}. Will .Min() work?

Answer 1

The following program

using System;
using System.Collections.Generic;
using System.Linq;

public class Test
{
    public static void Main()
    {
        List<int?> l = new List<int?>() {1, null, 2};
        Console.WriteLine(l.Min());
    }
}

outputs 1. If the list is however empty, or contains only null, the output is null.

So null counts as the biggest int for Min.