I would need to separate the signature from the body of a function in Python, i.e. :
def mult(a, b):
"Multiplication"
if a or b is None:
# border case
return None
else:
return a * b
(the function is there for demonstration only).
I know that inspect.getsourcelines(mult) will get me the full code, but I would like to have only the body, i.e. less the signature and the docstring:
if a or b is None:
# border case
return None
else:
return a * b
Is there an elegant way to obtain that, ideally using Python3 built-in parsing tools, rather than string manipulation?
As I don't know any function that does this, here is a homemade function that should work. I don't have time for more in-depth use-cases. So i'll leave my incomplete answer here.
def get_body(func):
""" Using the magic method __doc__, we KNOW the size of the docstring.
We then, just substract this from the total length of the function
"""
try:
lines_to_skip = len(func.__doc__.split('\n'))
except AttributeError:
lines_to_skip = 0
lines = getsourcelines(func)[0]
return ''.join( lines[lines_to_skip+1:] )
def ex_0(a, b):
""" Please !
Don't
Show
This
"""
if a or b is None:
# border case
return None
else:
return a * b
def ex_1(a, b):
''' Please !Don'tShowThis'''
if a or b is None:
# border case
return None
else:
return a * b
def ex_2(a, b):
if a or b is None:
# border case
return None
else:
return a * b
def ex_3(bullshit, hello):
pass
get_body(ex_0)
# if a or b is None:
# # border case
# return None
# else:
# return a * b
get_body(ex_1)
# if a or b is None:
# # border case
# return None
# else:
# return a * b
get_body(ex_2)
# if a or b is None:
# # border case
# return None
# else:
# return a * b
get_body(ex_3)
# pass
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