So, I have a bash script inside of which I'd like to have a conditional which depends on what a perl script returns. The idea behind my code is as follows:
for i in $(ls); do
if $(perl -e "if (\$i =~ /^.*(bleh|blah|bluh)/) {print 'true';}"); then
echo $i;
fi;
done
Currently, this always returns true, and when I tried it with [[]] around the if statement, I got errors. Any ideas anyone?
P.s. I know I can do this with grep, but it's just an example. I'd like to know how to have Bash use Perl output in general
P.p.s I know I can do this in two lines, setting the perl output to a variable and then testing for that variables value, but I'd rather avoid using that extra variable if possible. Seems wasteful.
If you use exit, you can just use an if directly. E.g.
if perl -e "exit 0 if (successful); exit 1"; then
echo $i;
fi;
0 is success, non-zero is failure, and 0 is the default if you don't call exit.
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