I wanted read a image using PIL.Image.open().But I've image in different path. The following is the path I've the python script
"D:\YY_Aadhi\holy-edge-master\hed\test.py"
The following is the path I've the image file.
"D:\YY_Aadhi\HED-BSDS\test\2018.jpg"
from PIL import Image
'''some code here'''
image = Image.open(????)
How should I fill the question mark to access the image file.
you can simply do
from PIL import Image
image = Image.open("D:\\YY_Aadhi\\HED-BSDS\\test\\2018.jpg")
or
from PIL import Image
directory = "D:\\YY_Aadhi\\HED-BSDS\\test\\2018.jpg"
image = Image.open(directory)
like this.
you have to write escape sequence twice in windows, when you want to define as directory. and It will be great if you try some stupid code. It helps you a lot.
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