I am using this loop structure but it fails to generate all the submatrix that are possible for any given 2D matrix with n rows and m columns.
for(i=0;i<n;i++)
{
for(j=0;j<m;j++)
{
System.out.println("sub-MATRIX:");
for(k=i;k<n;k++)
{
for(p=j;p<m;p++)
{
System.out.print(arr[k][p]+" ");
}
System.out.println();
}
}
}
Ex: Given matrix 3X3 : [[1 2 3],[4 5 6],[7 8 9]] Then its submatrix will be: for size 1: [1],[2],[3],[4],[5],[6],[7],[8],[9] for size 4: [[1,2],[4,5]],[[2,3],[5,6]],[[4,5],[7,8]] and [[5,6],[8,9]] and so on
You are missing a couple more loops to cover all cases. PrintMatyrix()
should have 2 nested loops for printing contents.
for (i = 1; i < n; ++i)
{
for (j = 1; j < m; ++j)
{
// we are at each sub matrix of size(i,j)
for (k = 0; k <= (n - i); ++k)
{
for (p = 0; p <= (m - j); ++p)
{
// we are at submatrix of size(i,j) starting at (k,p)
// assuming PrintMatrix(Matrix&, int rows, int cols, int r0, int c0);
PrintMatrix(arr, i, j, k, p);
}
}
}
}
If we have a matrix with dimensions M x N, and the sub matrix we are looking for is with K x L dimensions. If there is more optimized solution, please share.
for (int i = 0; i < m-k+1; i++) {
for (int j = 0; j < n-l+1; j++) {
for (int p = 0; p < k; p++) {
for(int q = 0; q < l; q++) {
System.out.print(arr[i+p][j+q] + " ");
}
System.out.println();
}
System.out.println("*****************");
}
}
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With