When deleting a key from a dictionary, I use:
if 'key' in my_dict: del my_dict['key'] Is there a one line way of doing this?
In Python, use list methods clear() , pop() , and remove() to remove items (elements) from a list. It is also possible to delete items using del statement by specifying a position or range with an index or slice.
If you call pop() on a key that doesn't exist, Python would return a KeyError . So only use pop(key) if you're confident that the key exists in the dictionary. If you are unsure if the key exists then put a value for the second, optional argument for pop() - the default value.
To delete a key regardless of whether it is in the dictionary, use the two-argument form of dict.pop():
my_dict.pop('key', None) This will return my_dict[key] if key exists in the dictionary, and None otherwise. If the second parameter is not specified (i.e. my_dict.pop('key')) and key does not exist, a KeyError is raised.
To delete a key that is guaranteed to exist, you can also use:
del my_dict['key'] This will raise a KeyError if the key is not in the dictionary.
Specifically to answer "is there a one line way of doing this?"
if 'key' in my_dict: del my_dict['key'] ...well, you asked ;-)
You should consider, though, that this way of deleting an object from a dict is not atomic—it is possible that 'key' may be in my_dict during the if statement, but may be deleted before del is executed, in which case del will fail with a KeyError. Given this, it would be safest to either use dict.pop or something along the lines of
try: del my_dict['key'] except KeyError: pass which, of course, is definitely not a one-liner.
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