I need to check the timeout of a SMTP-Server, but my socket just closes. What am I doing wrong? Here is my test for it:
#!/usr/bin/python
import smtplib
import time
import datetime
import socket
socket.setdefaulttimeout(1800)
now = time.time()
server = smtplib.SMTP()
server.set_debuglevel(1)
server.connect('mx.foo.bar','25')
(code,resp) = server.docmd('NOOP')
then = time.time()
print then-now
Lets hope this works.
Well, I haven't found any method to hold a smtp connection open with smtplib.
But, if you want to reuse a connection without closing (yes, opening a connection takes time, 2-3 secs), you can test the connection first. To do this, issue a NOOP command and test for status == 250. If not, then you can open a connection and send out your mail. And you can choose to not quit() the connection until you are done.
import smtplib
def create_conn():
conn = smtplib.SMTP('smtp.gmail.com', 587)
...
return conn
def is_connected(conn):
try:
status = conn.noop()[0]
except: # smtplib.SMTPServerDisconnected
status = -1
return True if status == 250 else False
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With