I want to do an AJAX call via jQuery load() and only once it returns, then fadeOut the old content and fadeIn the new content. I want to old content to remain showing until the new content is retrieved, at which point the fade Out/In is triggered.
Using:
$('#data').fadeOut('slow').load('/url/').fadeIn('slow');
the content fades in and out and a few moments the later the load() call returns, and the data updates, but the fade has already completed.
Use callbacks to the control the order of the calls.
var $data = $('#data');
$data.fadeOut('slow', function() {
$data.load('/url/', function() {
$data.fadeIn('slow');
});
});
(Note: I'm not 100% sure about if using var $data = ... and $data.doStuff() will actually work - if it does, it saves you from having to look up the div in the DOM tree every time, but if it doesn't, just remove the first line and use $('#data') everywhere...
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